Browns: Too early to call Cleveland most complete, but it may be true

The Browns may be the most complete NFL team, but it’s too soon to say.

You know you’re doing good when a former in-division rival speaks highly of you. On ESPN’s Get Up from Thursday morning, former Dallas Cowboy and Baltimore Ravens defensive linemen told the world that he felt the Browns were the most complete team in the NFL.

Similar sentiments were echoed by former Steelers safety Ryan Clark, who put the Browns in the top three in the AFC behind the Chiefs and the Bills. This is new territory for the Browns, who took a major step in the right direction in 2020.

That said, it’s way too soon to say the Brown is the most “complete” team in the NFL because each season is a new opportunity.

The Browns aren’t the most complete, but they could be.

I’ve never been a fan of proclaiming something as a fact before it could even be tested, let alone proven. To say that Cleveland is the most complete team in the NFL is impossible to prove. It might be true, they certainly made many great moves in the offseason to get to this place where they’re even being talked about in such a light.

That doesn’t mean it’s true though, not yet anyway Cleveland needs to get off the paper and get on the field to show the world what they are and aren’t. It’s one thing to be designated the most “complete” team before you’ve had to play a down of meaningful football, it’s another thing to evaluate yourself as such heading into the bye week.

The Browns could very well be that team, the pieces are there. The talent is there. Hopefully, the coaching is there. To be able to claim that you have no holes, however, you have to get tested on the field. Otherwise, it’s no different than 2019, when everyone said that Cleveland was SuperBowl contenders before Freddie Kitchens had even called a single series of pro football as a head coach.

It’s possible the Browns are the best team in the AFC, but let’s wait until they can prove they are before we start handing out platitudes.